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Fixed errors that seemed to afflict mysql 5.1.68 on windows with PHP 5.4 and IIS
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@@ -83,7 +83,7 @@ function is_using_availability($case_id)
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WHERE qa.questionnaire_id = c.questionnaire_id
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WHERE qa.questionnaire_id = c.questionnaire_id
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AND c.case_id = $case_id";
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AND c.case_id = $case_id";
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$rs = $db->CacheGetRow($sql);
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$rs = $db->GetRow($sql);
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if ($rs['cc'] > 0)
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if ($rs['cc'] > 0)
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return true;
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return true;
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@@ -582,7 +582,7 @@ function get_case_id($operator_id, $create = false)
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//add respondent details to respondent (if such details exist in the sample)
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//add respondent details to respondent (if such details exist in the sample)
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$sql = "INSERT INTO respondent (case_id,firstName,lastName,Time_zone_name)
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$sql = "INSERT INTO respondent (case_id,firstName,lastName,Time_zone_name)
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SELECT $case_id as case_id, s1.val as firstName, s2.val as lastName, s3.Time_zone_name as Time_zone_name
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SELECT $case_id as case_id, IFNULL(s1.val,'') as firstName, IFNULL(s2.val,'') as lastName, s3.Time_zone_name as Time_zone_name
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FROM sample as s3
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FROM sample as s3
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LEFT JOIN sample_var as s2 on (s2.sample_id = '{$r3['sample_id']}' and s2.type = 7)
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LEFT JOIN sample_var as s2 on (s2.sample_id = '{$r3['sample_id']}' and s2.type = 7)
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LEFT JOIN sample_var as s1 on (s1.sample_id = '{$r3['sample_id']}' and s1.type = 6)
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LEFT JOIN sample_var as s1 on (s1.sample_id = '{$r3['sample_id']}' and s1.type = 6)
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